(2x^3-4x^2+2)/2x-2

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Solution for (2x^3-4x^2+2)/2x-2 equation: 


x in (-oo:+oo)

x*((2*x^3-(4*x^2)+2)/2)-2 = 0

x*((2*x^3-4*x^2+2)/2)-2 = 0

(x*(2*x^3-4*x^2+2))/2-2 = 0

(x*(2*x^3-4*x^2+2))/2+(-2*2)/2 = 0

x*(2*x^3-4*x^2+2)-2*2 = 0

2*x^4-4*x^3+2*x-4 = 0

2*x^4-4*x^3+2*x-4 = 0

2*(x^4-2*x^3+x-2) = 0

x^4-2*x^3+x-2

x^3*(x-2)+x-2

(x^3+1)*(x-2)

2*(x^3+1)*(x-2) = 0

(2*(x^3+1)*(x-2))/2 = 0

(2*(x^3+1)*(x-2))/2 = 0 // * 2

2*(x^3+1)*(x-2) = 0

( x-2 )

x-2 = 0 // + 2

x = 2

( x^3+1 )

1*x^3 = -1 // : 1

x^3 = -1

x^3 = -1 // ^ 1/3

x = -1

x in { 2, -1 }

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